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  • {{title restriction|<math>\pi</math>|romanized}} ...mber]], as proved by Lindemann in 1882) denoted by the Greek letter <math>\pi</math>.
    8 KB (1,424 words) - 15:49, 17 February 2025
  • Given that <math>A_k = \frac {k(k - 1)}2\cos\frac {k(k - 1)\pi}2,</math> find <math>|A_{19} + A_{20} + \cdots + A_{98}|.</math> ...,x_2,x_3,x_4)</math> of positive odd [[integer]]s that satisfy <math>\sum_{i = 1}^4 x_i = 98.</math> Find <math>\frac n{100}.</math>
    7 KB (1,084 words) - 01:01, 28 November 2023
  • ...thocenter of the triangle. We consider the points <math>D</math> and <math>E</math> on the segments <math>AA_1</math> and <math>BC</math> such that <mat ...<math>a_i \in \{ -1, 1 \}</math>, such that <center><math>n = \sum_{1\leq i < j \leq k } a_ia_j</math>.</center>
    11 KB (1,779 words) - 13:57, 7 May 2012
  • {{AIME Problems|year=2008|n=I}} [[2008 AIME I Problems/Problem 1|Solution]]
    9 KB (1,536 words) - 23:46, 25 August 2023
  • ...Circle <math>\omega</math> intersects <math>\overline{AB}</math> at <math>E</math> and <math>B</math>, <math>\overline{BC}</math> at <math>B</math> and https://www.youtube.com/watch?v=n2tDvCQYK-I
    10 KB (1,654 words) - 17:53, 24 November 2024
  • If <math>3(4x+5\pi)=P</math> then <math>6(8x+10\pi)=</math> \text{(E) } 18P</math>
    16 KB (2,548 words) - 12:40, 19 February 2020
  • ...eorem. You wouldn't waste that much money to solve one problem. Therefore, I proved that you cannot use the Games theorem to solve problems. But using t ...dreadful. EDIT: He now eats gnats again. He thinks that they taste like pi(e). EDIT: He ate 3,141,592,653,589,793,238,462,643,383 so far.
    69 KB (11,805 words) - 19:49, 18 December 2019
  • ...e people will have reasonably inexpensive options for switching to cleaner power sources. Even now most families could switch to biomass for between <math>\ ...Alexis begins walking forward. As she walks, the tricorder displays at all times her distance from her starting point at the origin. When Alexis is <math>24
    7 KB (1,092 words) - 18:05, 17 December 2021
  • 4. The Infinity Numeral, PI, is the second deity of the Almighty Gmaas's heaven. 5. The Infinite Logarithm, E, is the third deity of the Almighty Gmaas's heaven.
    99 KB (14,096 words) - 22:49, 19 February 2025
  • <cmath>\sin^2{(\pi x)} + \sin^2{(\pi y)} > 1</cmath> ...rac{1+\sqrt{2}}{4} \qquad\textbf{(D)}\ \frac{\sqrt{5}-1}{2} \qquad\textbf{(E)}\ \frac{5}{8}</math>
    9 KB (1,536 words) - 03:29, 24 July 2024
  • label("$6\sqrt{3}$", (30,7.5), E); label("$E$", EE, N);
    17 KB (2,738 words) - 18:33, 6 January 2025
  • for (int i = 0; i < 7; ++i) { for (int j = 0; j < i; ++j) {
    21 KB (3,271 words) - 17:28, 16 November 2024
  • We apply the Power of a Point Theorem to <math>R</math> and <math>T:</math> ...orem on right <math>\triangle PRX.</math> Together, we conclude that <math>E=X.</math> Therefore, points <math>S,P,</math> and <math>X</math> must be co
    17 KB (2,612 words) - 13:54, 3 July 2023
  • ...mega = \cos\frac{2\pi}{7} + i \cdot \sin\frac{2\pi}{7},</math> where <math>i = \sqrt{-1}.</math> Find the value of the product<cmath>\prod_{k=0}^6 \left Man, What can I say? Mamba never out!
    10 KB (1,494 words) - 03:56, 2 February 2025
  • ...ng). He can be anything, but his form currently is a cat, though his godly power can turn him into anything, he just prefers to be a cat. As you read on, yo ...Pre-algebra class. He enters every class by posting a meme and announcing "I have arrived!" Sseraj is the human servant of Gmaas and is one of only 5 en
    89 KB (15,007 words) - 14:02, 19 February 2025
  • (i) <math>1</math> ring changed position (i.e., that ring is transferred from one peg to another) ...th>IJ</math>. There exist a circle <math>\Omega_1</math> centered at <math>I</math> and tangent to <math>\Omega</math> at point <math>K</math>. <math>IO
    64 KB (10,564 words) - 21:17, 19 February 2025
  • Let <math>\triangle</math><math>ABC</math> have incenter <math>I</math>, circumcenter <math>O</math>, inradius <math>6</math>, and circumrad Start off by (of course) drawing a diagram! Let <math>I</math> and <math>O</math> be the incenter and circumcenters of triangle <ma
    22 KB (3,762 words) - 04:19, 25 February 2025
  • ...eorem. You wouldn't waste that much money to solve one problem. Therefore, I proved that you cannot use the Games theorem to solve problems. But using t ...dreadful. EDIT: He now eats gnats again. He thinks that they taste like pi(e). EDIT: He ate 3,141,592,653,589,793,238,462,643,383 so far.
    69 KB (11,828 words) - 18:26, 3 September 2024
  • ...f{(B) } 12 \qquad \textbf{(C) } 16 \qquad \textbf{(D) } 18 \qquad \textbf{(E) } 21</math> ...>720</math> itself, we know that the answer is <math>7+6+8=\boxed{\textbf{(E) } 21}</math>.
    6 KB (1,013 words) - 14:37, 15 February 2025