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- {{title restriction|<math>\pi</math>|romanized}} ...mber]], as proved by Lindemann in 1882) denoted by the Greek letter <math>\pi</math>.8 KB (1,424 words) - 15:49, 17 February 2025
- Given that <math>A_k = \frac {k(k - 1)}2\cos\frac {k(k - 1)\pi}2,</math> find <math>|A_{19} + A_{20} + \cdots + A_{98}|.</math> ...,x_2,x_3,x_4)</math> of positive odd [[integer]]s that satisfy <math>\sum_{i = 1}^4 x_i = 98.</math> Find <math>\frac n{100}.</math>7 KB (1,084 words) - 01:01, 28 November 2023
- ...thocenter of the triangle. We consider the points <math>D</math> and <math>E</math> on the segments <math>AA_1</math> and <math>BC</math> such that <mat ...<math>a_i \in \{ -1, 1 \}</math>, such that <center><math>n = \sum_{1\leq i < j \leq k } a_ia_j</math>.</center>11 KB (1,779 words) - 13:57, 7 May 2012
- {{AIME Problems|year=2008|n=I}} [[2008 AIME I Problems/Problem 1|Solution]]9 KB (1,536 words) - 23:46, 25 August 2023
- ...Circle <math>\omega</math> intersects <math>\overline{AB}</math> at <math>E</math> and <math>B</math>, <math>\overline{BC}</math> at <math>B</math> and https://www.youtube.com/watch?v=n2tDvCQYK-I10 KB (1,654 words) - 17:53, 24 November 2024
- If <math>3(4x+5\pi)=P</math> then <math>6(8x+10\pi)=</math> \text{(E) } 18P</math>16 KB (2,548 words) - 12:40, 19 February 2020
- ...eorem. You wouldn't waste that much money to solve one problem. Therefore, I proved that you cannot use the Games theorem to solve problems. But using t ...dreadful. EDIT: He now eats gnats again. He thinks that they taste like pi(e). EDIT: He ate 3,141,592,653,589,793,238,462,643,383 so far.69 KB (11,805 words) - 19:49, 18 December 2019
- ...e people will have reasonably inexpensive options for switching to cleaner power sources. Even now most families could switch to biomass for between <math>\ ...Alexis begins walking forward. As she walks, the tricorder displays at all times her distance from her starting point at the origin. When Alexis is <math>247 KB (1,092 words) - 18:05, 17 December 2021
- 4. The Infinity Numeral, PI, is the second deity of the Almighty Gmaas's heaven. 5. The Infinite Logarithm, E, is the third deity of the Almighty Gmaas's heaven.99 KB (14,096 words) - 22:49, 19 February 2025
- <cmath>\sin^2{(\pi x)} + \sin^2{(\pi y)} > 1</cmath> ...rac{1+\sqrt{2}}{4} \qquad\textbf{(D)}\ \frac{\sqrt{5}-1}{2} \qquad\textbf{(E)}\ \frac{5}{8}</math>9 KB (1,536 words) - 03:29, 24 July 2024
- label("$6\sqrt{3}$", (30,7.5), E); label("$E$", EE, N);17 KB (2,738 words) - 18:33, 6 January 2025
- for (int i = 0; i < 7; ++i) { for (int j = 0; j < i; ++j) {21 KB (3,271 words) - 17:28, 16 November 2024
- We apply the Power of a Point Theorem to <math>R</math> and <math>T:</math> ...orem on right <math>\triangle PRX.</math> Together, we conclude that <math>E=X.</math> Therefore, points <math>S,P,</math> and <math>X</math> must be co17 KB (2,612 words) - 13:54, 3 July 2023
- ...mega = \cos\frac{2\pi}{7} + i \cdot \sin\frac{2\pi}{7},</math> where <math>i = \sqrt{-1}.</math> Find the value of the product<cmath>\prod_{k=0}^6 \left Man, What can I say? Mamba never out!10 KB (1,494 words) - 03:56, 2 February 2025
- ...ng). He can be anything, but his form currently is a cat, though his godly power can turn him into anything, he just prefers to be a cat. As you read on, yo ...Pre-algebra class. He enters every class by posting a meme and announcing "I have arrived!" Sseraj is the human servant of Gmaas and is one of only 5 en89 KB (15,007 words) - 14:02, 19 February 2025
- (i) <math>1</math> ring changed position (i.e., that ring is transferred from one peg to another) ...th>IJ</math>. There exist a circle <math>\Omega_1</math> centered at <math>I</math> and tangent to <math>\Omega</math> at point <math>K</math>. <math>IO64 KB (10,564 words) - 21:17, 19 February 2025
- Let <math>\triangle</math><math>ABC</math> have incenter <math>I</math>, circumcenter <math>O</math>, inradius <math>6</math>, and circumrad Start off by (of course) drawing a diagram! Let <math>I</math> and <math>O</math> be the incenter and circumcenters of triangle <ma22 KB (3,762 words) - 04:19, 25 February 2025
- ...eorem. You wouldn't waste that much money to solve one problem. Therefore, I proved that you cannot use the Games theorem to solve problems. But using t ...dreadful. EDIT: He now eats gnats again. He thinks that they taste like pi(e). EDIT: He ate 3,141,592,653,589,793,238,462,643,383 so far.69 KB (11,828 words) - 18:26, 3 September 2024
- ...f{(B) } 12 \qquad \textbf{(C) } 16 \qquad \textbf{(D) } 18 \qquad \textbf{(E) } 21</math> ...>720</math> itself, we know that the answer is <math>7+6+8=\boxed{\textbf{(E) } 21}</math>.6 KB (1,013 words) - 14:37, 15 February 2025