Difference between revisions of "1950 AHSME Problems/Problem 2"
Loverslane22 (talk | contribs) (Created page with "==Problem== Let <math> R=gS-4 </math>. When <math>S=8</math>, <math>R=16</math>. When <math>S=10</math>, <math>R</math> is equal to: <math> \textbf{(A)}\ 11\qquad\textbf{(B)}\ ...") |
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==Solution== | ==Solution== | ||
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+ | Our first procedure is to find the value of <math>g</math>. With the given variables' values, we can see that <math>8g-4=16</math> so <math>g=\frac{20}{8}=\frac{5}{2}</math>. | ||
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+ | With that, we can replace <math>g</math> with <math>\frac{5}{2}</math>. When <math>S=10</math>, we can see that <math>10\times\frac{5}{2}-4=\frac{50}{2}-4=25-4=\boxed{\text{(D) 21}}</math>. | ||
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+ | ==See Also== | ||
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+ | {{AHSME box|year=1950|num-b=1|num-a=3}} |
Revision as of 11:54, 22 September 2011
Problem
Let . When , . When , is equal to:
Solution
Our first procedure is to find the value of . With the given variables' values, we can see that so .
With that, we can replace with . When , we can see that .
See Also
1950 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
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All AHSME Problems and Solutions |