Difference between revisions of "1954 AHSME Problems/Problem 7"

m (Minor LaTeX error)
 
Line 7: Line 7:
 
== Solution ==
 
== Solution ==
 
Since she saved <math>\textdollar{2.50}</math> and spent <math>\textdollar{25}</math>, the original price of the dress was <math>\textdollar{27.50}</math>. The percent saved can be modeled as <math>27.5x=2.5</math>, so the answer is <math>x=\frac{2.5}{27.5}</math> or <math>\frac{1}{11}</math>, approximately <math>9\% \implies \textbf{(B)}</math>
 
Since she saved <math>\textdollar{2.50}</math> and spent <math>\textdollar{25}</math>, the original price of the dress was <math>\textdollar{27.50}</math>. The percent saved can be modeled as <math>27.5x=2.5</math>, so the answer is <math>x=\frac{2.5}{27.5}</math> or <math>\frac{1}{11}</math>, approximately <math>9\% \implies \textbf{(B)}</math>
 +
 +
 +
{{AHSME 50p box|year=1954|num-b=6|num-a=8}}
 +
{{MAA Notice}}

Latest revision as of 17:49, 15 April 2017

Problem 7

A housewife saved $\textdollar{2.50}$ in buying a dress on sale. If she spent $\textdollar{25}$ for the dress, she saved about:

$\textbf{(A)}\ 8 \% \qquad \textbf{(B)}\ 9 \% \qquad \textbf{(C)}\ 10 \% \qquad \textbf{(D)}\ 11 \% \qquad \textbf{(E)}\ 12\%$

Solution

Since she saved $\textdollar{2.50}$ and spent $\textdollar{25}$, the original price of the dress was $\textdollar{27.50}$. The percent saved can be modeled as $27.5x=2.5$, so the answer is $x=\frac{2.5}{27.5}$ or $\frac{1}{11}$, approximately $9\% \implies \textbf{(B)}$


1954 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 6
Followed by
Problem 8
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50
All AHSME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png

Invalid username
Login to AoPS