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# 1970 AHSME Problems/Problem 2

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## Problem

A square and a circle have equal perimeters. The ratio of the area of the circle to the are of the square is

$\text{(A) } \frac{4}{\pi}\quad \text{(B) } \frac{\pi}{\sqrt{2}}\quad \text{(C) } \frac{4}{1}\quad \text{(D) } \frac{\sqrt{2}}{\pi}\quad \text{(E) } \frac{\pi}{4}$

## Solution

$\fbox{A}$