1989 AJHSME Problems/Problem 1
Revision as of 19:44, 26 May 2009 by 5849206328x (talk | contribs) (New page: ==Problem== <math>(1+11+21+31+41)+(9+19+29+39+49)=</math> <math>\text{(A)}\ 150 \qquad \text{(B)}\ 199 \qquad \text{(C)}\ 200 \qquad \text{(D)}\ 249 \qquad \text{(E)}\ 250</math> ==Solu...)
Problem
Solution
We make use of the associative and commutative properties of addition to rearrange the sum as
See Also
| 1989 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
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| All AJHSME/AMC 8 Problems and Solutions | ||
