1992 AHSME Problems/Problem 5

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Problem

$6^6+6^6+6^6+6^6+6^6+6^6=$

$\text{(A) } 6^6 \quad \text{(B) } 6^7\quad \text{(C) } 36^6\quad \text{(D) } 6^{36}\quad \text{(E) } 36^{36}$

Solution

We notice that $6^6+6^6+6^6+6^6+6^6+6^6=6(6^6)=\boxed{\textbf{(B) }6^7}$.

See also

1992 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 4
Followed by
Problem 6
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