Difference between revisions of "1992 AHSME Problems/Problem 7"

Latest revision as of 02:24, 20 February 2018

The ratio of $w$ to $x$ is $4:3$ , of $y$ to $z$ is $3:2$ and of $z$ to $x$ is $1:6$ . What is the ratio of $w$ to $y$ ?

$\text{(A) } 1:3\quad \text{(B) } 16:3\quad \text{(C) } 20:3\quad \text{(D) } 27:4\quad \text{(E) } 12:1$

$\fbox{B}$

Converting from ratios to fractions

$\frac{w}{x}=\frac{4}{3}$ , $\frac{y}{z}=\frac{3}{2}$ , $\frac{z}{x}=\frac{1}{6}$

$\frac{y}{z} \cdot \frac{z}{x} = \frac{3}{2} \cdot \frac{1}{6}$

$\frac{y}{x} = \frac{1}{4}$

$\frac{(\frac{w}{x})}{(\frac{y}{x})}=\frac{\frac{4}{3}}{\frac{1}{4}}$

$\frac{w}{y} = \frac{16}{3}$

$w$ to $y$ is $16:3$

1992 AHSME (Problems • Answer Key • Resources)
Preceded by Problem 6	Followed by Problem 8
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30
All AHSME Problems and Solutions

@@ Line 27: / Line 27: @@
 <math>\frac{w}{y} = \frac{16}{3}</math>
-<math>w</math> to <math>x</math> is <math>16:3</math>
+<math>w</math> to <math>y</math> is <math>16:3</math>
 == See also ==