# 1996 AJHSME Problems/Problem 19

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## Problem

The pie charts below indicate the percent of students who prefer golf, bowling, or tennis at East Junior High School and West Middle School. The total number of students at East is 2000 and at West, 2500. In the two schools combined, the percent of students who prefer tennis is $[asy] unitsize(18); draw(circle((0,0),4)); draw(circle((9,0),4)); draw((-4,0)--(0,0)--4*dir(352.8)); draw((0,0)--4*dir(100.8)); draw((5,0)--(9,0)--(4*dir(324)+(9,0))); draw((9,0)--(4*dir(50.4)+(9,0))); label("48\%",(0,-1),S); label("bowling",(0,-2),S); label("30\%",(1.5,1.5),N); label("golf",(1.5,0.5),N); label("22\%",(-2,1.5),N); label("tennis",(-2,0.5),N); label("40\%",(8.5,-1),S); label("tennis",(8.5,-2),S); label("24\%",(10.5,0.5),E); label("golf",(10.5,-0.5),E); label("36\%",(7.8,1.7),N); label("bowling",(7.8,0.7),N); label("\textbf{East JHS}",(0,-4),S); label("\textbf{2000 students}",(0,-5),S); label("\textbf{West MS}",(9,-4),S); label("\textbf{2500 students}",(9,-5),S); [/asy]$ $\text{(A)}\ 30\% \qquad \text{(B)}\ 31\% \qquad \text{(C)}\ 32\% \qquad \text{(D)}\ 33\% \qquad \text{(E)}\ 34\%$

## Solution

In the first school, $2000 \cdot 22\% = 2000 \cdot 0.22 = 440$ students prefer tennis.

In the second school, $2500 \cdot 40\% = 2500 \cdot 0.40 = 1000$ students prefer tennis.

In total, $440 + 1000 = 1440$ students prefer tennis out of a total of $2000 + 2500 = 4500$ students

This means $\frac{1440}{4500}\cdot 100\% = \frac{32}{100} \cdot 100\% = 32\%$ of the students in both schools prefer tennis, giving answer $\boxed{C}$.

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