Difference between revisions of "1998 AHSME Problems/Problem 6"

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== Problem 6 ==
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== Problem ==
 
If <math>1998</math> is written as a product of two positive integers whose difference is as small as possible, then the difference is  
 
If <math>1998</math> is written as a product of two positive integers whose difference is as small as possible, then the difference is  
  
 
<math> \mathrm{(A) \ }8 \qquad \mathrm{(B) \ }15 \qquad \mathrm{(C) \ }17 \qquad \mathrm{(D) \ }47 \qquad \mathrm{(E) \ } 93</math>
 
<math> \mathrm{(A) \ }8 \qquad \mathrm{(B) \ }15 \qquad \mathrm{(C) \ }17 \qquad \mathrm{(D) \ }47 \qquad \mathrm{(E) \ } 93</math>
  
[[1998 AHSME Problems/Problem 6|Solution]]
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==Solution==
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{{solution}}
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==See Also==
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{{AHSME box|year=1998|num-b=5|num-a=7}}

Revision as of 15:35, 6 June 2011

Problem

If $1998$ is written as a product of two positive integers whose difference is as small as possible, then the difference is

$\mathrm{(A) \ }8 \qquad \mathrm{(B) \ }15 \qquad \mathrm{(C) \ }17 \qquad \mathrm{(D) \ }47 \qquad \mathrm{(E) \ } 93$

Solution

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See Also

1998 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 5
Followed by
Problem 7
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All AHSME Problems and Solutions