Difference between revisions of "2001 AMC 10 Problems/Problem 7"

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<math> 200/10000=2/100= \boxed{\textbf{(C) }0.02} </math>.
 
<math> 200/10000=2/100= \boxed{\textbf{(C) }0.02} </math>.
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== See Also ==
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{{AMC10 box|year=2001|num-b=6|num-a=8}}

Revision as of 16:19, 16 March 2011

Problem

When the decimal point of a certain positive decimal number is moved four places to the right, the new number is four times the reciprocal of the original number. What is the original number?

$\textbf{(A) }0.0002\qquad\textbf{(B) }0.002\qquad\textbf{(C) }0.02\qquad\textbf{(D) }0.2\qquad\textbf{(E) }2$

Solution

We can write our equation as:

$\frac{x}{10000}=\frac{4}{x}$

Cross-multiply and solve for $x$.

$x^2=40000 \implies x=200$.

$200/10000=2/100= \boxed{\textbf{(C) }0.02}$.

See Also

2001 AMC 10 (ProblemsAnswer KeyResources)
Preceded by
Problem 6
Followed by
Problem 8
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions
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