Difference between revisions of "2001 USAMO Problems/Problem 2"

Revision as of 16:11, 10 September 2008

Problem

Let $ABC$ be a triangle and let $\omega$ be its incircle. Denote by $D_1$ and $E_1$ the points where $\omega$ is tangent to sides $BC$ and $AC$ , respectively. Denote by $D_2$ and $E_2$ the points on sides $BC$ and $AC$ , respectively, such that $CD_2 = BD_1$ and $CE_2 = AE_1$ , and denote by $P$ the point of intersection of segments $AD_2$ and $BE_2$ . Circle $\omega$ intersects segment $AD_2$ at two points, the closer of which to the vertex $A$ is denoted by $Q$ . Prove that $AQ = D_2P$ .

Solution

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 == See also ==
-{{USAMO box|year=2001|num-b=1|num-a=3}}
+{{USAMO newbox|year=2001|num-b=1|num-a=3}}
 [[Category:Olympiad Geometry Problems]]

2001 USAMO (Problems • Resources)
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Difference between revisions of "2001 USAMO Problems/Problem 2"

Revision as of 16:11, 10 September 2008

Problem

Solution

See also