Difference between revisions of "2002 AMC 10A Problems/Problem 19"

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==See Also==
==See Also==
{{AMC10 box|ab=A|year=2002|num-b=17|num-a=19}}
{{AMC10 box|ab=A|year=2002|num-b=18|num-a=20}}
[[Category:Introductory Geometry Problems]]
[[Category:Introductory Geometry Problems]]

Revision as of 17:08, 28 July 2011


Spot's doghouse has a regular hexagonal base that measures one yard on each side. He is tethered to a vertex with a two-yard rope. What is the area, in square yards, of the region outside of the doghouse that Spot can reach?

$\text{(A)}\ 2\pi/3 \qquad \text{(B)}\ 2\pi \qquad \text{(C)}\ 5\pi/2 \qquad \text{(D)}\ 8\pi/3 \qquad \text{(E)}\ 3\pi$


Part of what Spot can reach is $\frac{240}{360}=\frac{2}{3}$ of a circle with radius 2, which gives him $\frac{8\pi}{3}$. He can also reach two $\frac{60}{360}$ parts of a unit circle, which combines to give $\frac{\pi}{3}$. The total area is then $3\pi$, which gives $\boxed{\text{(E)}}$.

See Also

2002 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
Problem 18
Followed by
Problem 20
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All AMC 10 Problems and Solutions
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