Difference between revisions of "2002 AMC 12A Problems/Problem 23"
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==Problem== | ==Problem== | ||
| − | + | In triangle <math>ABC</math> , side <math>AC</math> and the perpendicular bisector of <math>BC</math> meet in point D, and bisects <math><ABC. If </math>AD=9<math> and </math>DC=7<math>, what is the area of triangle ABD? | |
| + | </math>A) 14<math> </math>B) 21<math> </math>C)28<math> </math>D)14\sqrt5<math> </math>E)28\sqrt5$ | ||
==Solution== | ==Solution== | ||
Revision as of 18:52, 17 January 2010
Problem
In triangle 
, side 
and the perpendicular bisector of 
meet in point D, and bisects 
AD=9
DC=7
A) 14$$ (Error compiling LaTeX. Unknown error_msg)B) 21$$ (Error compiling LaTeX. Unknown error_msg)C)28$$ (Error compiling LaTeX. Unknown error_msg)D)14\sqrt5$$ (Error compiling LaTeX. Unknown error_msg)E)28\sqrt5$
Solution
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See Also
| 2002 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by Problem 24 |
Followed by Last Problem |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
