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Difference between revisions of "2003 AMC 12B Problems"

(Problem 1)
Line 4: Line 4:
 
<cmath>\frac{2-4+6-8+10-12+14}{3-6+9-12+15-18+21}</cmath>?
 
<cmath>\frac{2-4+6-8+10-12+14}{3-6+9-12+15-18+21}</cmath>?
  
\[
+
<math>
 
\text {(A) } -1 \qquad \text {(B) } -\frac{2}{3} \qquad \text {(C) } \frac{2}{3} \qquad \text {(D) } 1 \qquad \text {(E) } \frac{14}{3}
 
\text {(A) } -1 \qquad \text {(B) } -\frac{2}{3} \qquad \text {(C) } \frac{2}{3} \qquad \text {(D) } 1 \qquad \text {(E) } \frac{14}{3}
\]
+
</math>
  
 
[[2003 AMC 12B Problems/Problem 1|Solution]]
 
[[2003 AMC 12B Problems/Problem 1|Solution]]

Revision as of 11:40, 27 November 2007