Difference between revisions of "2011 AMC 12A Problems/Problem 2"
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== Problem == | == Problem == | ||
+ | There are <math>5</math> coins placed flat on a table according to the figure. What is the order of the coins from top to bottom? | ||
+ | |||
+ | <asy> | ||
+ | size(100); defaultpen(linewidth(.8pt)+fontsize(8pt)); | ||
+ | draw(arc((0,1), 1.2, 25, 214)); | ||
+ | draw(arc((.951,.309), 1.2, 0, 360)); | ||
+ | draw(arc((.588,-.809), 1.2, 132, 370)); | ||
+ | draw(arc((-.588,-.809), 1.2, 75, 300)); | ||
+ | draw(arc((-.951,.309), 1.2, 96, 228)); | ||
+ | label("$A$",(0,1),NW); label("$B$",(-1.1,.309),NW); label("$C$",(.951,.309),E); label("$D$",(-.588,-.809),W); label("$E$",(.588,-.809),S); | ||
+ | </asy> | ||
+ | |||
+ | <math>\textbf{(A)}\ (C, A, E, D, B) \qquad \textbf{(B)}\ (C, A, D, E, B) \qquad \textbf{(C)}\ (C, D, E, A, B) \qquad \textbf{(D)}\ (C, E, A, D, B) \qquad \textbf{(E)}\ (C, E, D, A, B) </math> | ||
+ | |||
== Solution == | == Solution == | ||
+ | By careful inspection and common sense, the answer is <math>\textbf{(E)}</math>. | ||
+ | |||
== See also == | == See also == | ||
− | {{AMC12 box|year=2011| | + | {{AMC12 box|year=2011|num-b=1|num-a=3|ab=A}} |
+ | |||
+ | [[Category:Introductory Combinatorics Problems]] | ||
+ | {{MAA Notice}} |
Revision as of 01:06, 19 October 2020
Problem
There are coins placed flat on a table according to the figure. What is the order of the coins from top to bottom?
Solution
By careful inspection and common sense, the answer is .
See also
2011 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 1 |
Followed by Problem 3 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.