Difference between revisions of "2011 AMC 12A Problems/Problem 9"
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== Problem == | == Problem == | ||
| + | At a twins and triplest convention, there were <math>9</math> sets of twins and <math>6</math> sets of triplets, all from different families. Each twin shook hands with all the twins except his/her siblings and with half the triplets. Each triplet shook hands with all the triplets except his/her siblings and with half the twins. How many handshakes took place? | ||
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| + | <math> | ||
| + | \textbf{(A)}\ 324 \qquad | ||
| + | \textbf{(B)}\ 441 \qquad | ||
| + | \textbf{(C)}\ 630 \qquad | ||
| + | \textbf{(D)}\ 648 \qquad | ||
| + | \textbf{(E)}\ 882 </math> | ||
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== Solution == | == Solution == | ||
== See also == | == See also == | ||
{{AMC12 box|year=2011|num-b=8|num-a=10|ab=A}} | {{AMC12 box|year=2011|num-b=8|num-a=10|ab=A}} | ||
Revision as of 02:33, 10 February 2011
Problem
At a twins and triplest convention, there were 
sets of twins and 
sets of triplets, all from different families. Each twin shook hands with all the twins except his/her siblings and with half the triplets. Each triplet shook hands with all the triplets except his/her siblings and with half the twins. How many handshakes took place?
Solution
See also
| 2011 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by Problem 8 |
Followed by Problem 10 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
