Difference between revisions of "2011 AMC 8 Problems/Problem 5"

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What time was it <math>2011</math> minutes after midnight on January 1, 2011?
 
What time was it <math>2011</math> minutes after midnight on January 1, 2011?
  
<math>\text{(A) January 1 at 9:31PM}</math>
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<math>\textbf{(A)}\ \text{January 1 at 9:31PM}</math>
  
<math>\text{(B) January 1 at 11:51PM}</math>  
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<math>\textbf{(B)}\ \text{January 1 at 11:51PM}</math>  
  
<math>\text{(C) January 2 at 3:11AM}</math>  
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<math>\textbf{(C)}\ \text{January 2 at 3:11AM}</math>  
  
<math>\text{(D) January 2 at 9:31AM}</math>  
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<math>\textbf{(D)}\ \text{January 2 at 9:31AM}</math>  
  
<math>\text{(E) January 2 at 6:01PM}</math>
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<math>\textbf{(E)}\ \text{January 2 at 6:01PM}</math>
  
 
==Solution==
 
==Solution==
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There are <math>60</math> minutes in an hour. <math>2011/60=33\text{r}31,</math> or <math>33</math> hours and <math>31</math> minutes. There are <math>24</math> hours in a day, so the time is <math>9</math> hours and <math>31</math> minutes after midnight on January 2, 2011. <math>\Rightarrow \boxed{\textbf{(D)}}</math>
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2011|num-b=4|num-a=6}}
 
{{AMC8 box|year=2011|num-b=4|num-a=6}}

Revision as of 17:52, 25 November 2011

What time was it $2011$ minutes after midnight on January 1, 2011?

$\textbf{(A)}\ \text{January 1 at 9:31PM}$

$\textbf{(B)}\ \text{January 1 at 11:51PM}$

$\textbf{(C)}\ \text{January 2 at 3:11AM}$

$\textbf{(D)}\ \text{January 2 at 9:31AM}$

$\textbf{(E)}\ \text{January 2 at 6:01PM}$

Solution

There are $60$ minutes in an hour. $2011/60=33\text{r}31,$ or $33$ hours and $31$ minutes. There are $24$ hours in a day, so the time is $9$ hours and $31$ minutes after midnight on January 2, 2011. $\Rightarrow \boxed{\textbf{(D)}}$

See Also

2011 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 4
Followed by
Problem 6
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions
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