Difference between revisions of "2016 AMC 10B Problems/Problem 23"

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==Solution==
 
==Solution==
 
<math>\textbf{(C)}\ \frac{11}{27}</math>
 
<math>\textbf{(C)}\ \frac{11}{27}</math>
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==See Also==
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{{AMC10 box|year=2016|ab=B|num-b=22|num-a=24}}
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{{MAA Notice}}

Revision as of 13:24, 21 February 2016

Problem

In regular hexagon $ABCDEF$, points $W$, $X$, $Y$, and $Z$ are chosen on sides $\overline{BC}$, $\overline{CD}$, $\overline{EF}$, and $\overline{FA}$ respectively, so lines $AB$, $ZW$, $YX$, and $ED$ are parallel and equally spaced. What is the ratio of the area of hexagon $WCXYFZ$ to the area of hexagon $ABCDEF$?

$\textbf{(A)}\ \frac{1}{3}\qquad\textbf{(B)}\ \frac{10}{27}\qquad\textbf{(C)}\ \frac{11}{27}\qquad\textbf{(D)}\ \frac{4}{9}\qquad\textbf{(E)}\ \frac{13}{27}$


Solution

$\textbf{(C)}\ \frac{11}{27}$


See Also

2016 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
Problem 22
Followed by
Problem 24
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

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