Difference between revisions of "2016 AMC 12B Problems/Problem 5"

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By: dragonfly
 
By: dragonfly
  
To find what day of the week it is in <math>919</math> days, we have to divide <math>919</math> by <math>7</math> to see the remainder, and then add the remainder to the current day. We get that <math>\frac{919}{7}</math> has a remainder of 2, so we increase the current day by <math>2</math> to get <math>\boxed{\textbf{(B)} \text{Saturday}}</math>
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To find what day of the week it is in <math>919</math> days, we have to divide <math>919</math> by <math>7</math> to see the remainder, and then add the remainder to the current day. We get that <math>\frac{919}{7}</math> has a remainder of 2, so we increase the current day by <math>2</math> to get <math>\boxed{\textbf{(B)}\ \text{Saturday}}</math>.
  
Question: Why don't we have to account for leap years?
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Note that the dates themselves (and thus leap years) can be ignored, as we only need the number of days that passed to figure out the day of the week.
 
 
Answer: Although 1812 is a leap year, June 18 is after February 29. Plus, it gives you the number of days...so...
 
  
 
==See Also==
 
==See Also==
 
{{AMC12 box|year=2016|ab=B|num-b=4|num-a=6}}
 
{{AMC12 box|year=2016|ab=B|num-b=4|num-a=6}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 22:59, 6 November 2021

Problem

The War of $1812$ started with a declaration of war on Thursday, June $18$, $1812$. The peace treaty to end the war was signed $919$ days later, on December $24$, $1814$. On what day of the week was the treaty signed?

$\textbf{(A)}\ \text{Friday} \qquad \textbf{(B)}\ \text{Saturday} \qquad \textbf{(C)}\ \text{Sunday} \qquad \textbf{(D)}\ \text{Monday} \qquad \textbf{(E)}\ \text{Tuesday}$

Solution

By: dragonfly

To find what day of the week it is in $919$ days, we have to divide $919$ by $7$ to see the remainder, and then add the remainder to the current day. We get that $\frac{919}{7}$ has a remainder of 2, so we increase the current day by $2$ to get $\boxed{\textbf{(B)}\ \text{Saturday}}$.

Note that the dates themselves (and thus leap years) can be ignored, as we only need the number of days that passed to figure out the day of the week.

See Also

2016 AMC 12B (ProblemsAnswer KeyResources)
Preceded by
Problem 4
Followed by
Problem 6
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions

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