Difference between revisions of "2018 AMC 8 Problems/Problem 11"
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<math>\textbf{(A) } \frac{1}{3} \qquad \textbf{(B) } \frac{2}{5} \qquad \textbf{(C) } \frac{7}{15} \qquad \textbf{(D) } \frac{1}{2} \qquad \textbf{(E) } \frac{2}{3}</math> | <math>\textbf{(A) } \frac{1}{3} \qquad \textbf{(B) } \frac{2}{5} \qquad \textbf{(C) } \frac{7}{15} \qquad \textbf{(D) } \frac{1}{2} \qquad \textbf{(E) } \frac{2}{3}</math> | ||
| − | + | {{AMC8 box|year=2018|num-b=10|num-a=12}} | |
Revision as of 15:07, 21 November 2018
Problem 11
Abby, Bridget, and four of their classmates will be seated in two rows of three for a group picture, as shown.
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| 2018 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 10 |
Followed by Problem 12 | |
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| All AJHSME/AMC 8 Problems and Solutions | ||
