Difference between revisions of "2019 AIME I Problems/Problem 6"
(→Solution (Similar triangles)) |
(→Solution (Similar triangles)) |
||
Line 26: | Line 26: | ||
label("O", shift((1,1))*O, NNE); | label("O", shift((1,1))*O, NNE); | ||
label("28", scale(1/2)*L, W); | label("28", scale(1/2)*L, W); | ||
+ | label("65", ((M.x+N.x)/2, (M.y+N.y)/2), NE); | ||
</asy> | </asy> | ||
+ | |||
+ | First, let <math>P</math> be the intersection of <math>LO</math> and <math>KN</math>. Note that <math>m\angle KPL = 90^{\circ}</math> as given in the problem. | ||
==Video Solution== | ==Video Solution== |
Revision as of 09:51, 15 March 2019
Problem 6
In convex quadrilateral side is perpendicular to diagonal , side is perpendicular to diagonal , , and . The line through perpendicular to side intersects diagonal at with . Find .
Solution (Similar triangles)
(writing this, don't edit)
First, let be the intersection of and . Note that as given in the problem.
Video Solution
Video Solution: https://www.youtube.com/watch?v=0AXF-5SsLc8
See Also
2019 AIME I (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All AIME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.