# Difference between revisions of "2019 AIME I Problems/Problem 9"

The 2019 AIME I takes place on March 13, 2019.

## Problem 9

Let $\tau (n)$ denote the number of positive integer divisors of $n$. Find the sum of the six least positive integers $n$ that are solutions to $\tau (n) + \tau (n+1) = 7$.