2019 AIME I Problems/Problem 9

Revision as of 19:36, 14 March 2019 by Krisha12 (talk | contribs) (Problem 9)

The 2019 AIME I takes place on March 13, 2019.

Problem 9

Let $\tau (n)$ denote the number of positive integer divisors of $n$. Find the sum of the six least positive integers $n$ that are solutions to $\tau (n) + \tau (n+1) = 7$.

Solution

See Also

2019 AIME I (ProblemsAnswer KeyResources)
Preceded by
Problem 8
Followed by
Problem 10
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
All AIME Problems and Solutions

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