Replacing OH with any line through the centroid G???
by Sid-darth-vater, Jun 6, 2025, 3:25 PM
Let
be the circumcenter and
the orthocenter of an acute triangle
Prove that the area of one of the triangles
and
is equal to the sum of the areas of the other two.
Basically, I was able to solve this question using the centroid but without moving line OH.
Here is a quick sketch of what I did: All triangles have base of OH so you just have to show that two altitudes to line OH add up to the third. WLOG, let triangle AOH have the largest area and let A', B', C' denote altitudes from their respective points to line OH. This is euler line so G also lies on OH. Let AG instersect BC at M (which is a median) and let M' denote altitude onto OH. Note that M'M = 0.5 * AA' and since BCC'B' is trapezoid and M is midpoint, MM' = 0.5 (BB' + CC') so equate the two and we are done.
In Evan Chen's EGMO book, he says you can replace line
with any line through the centroid
and I have no clue as to why that is true. Plz help





Basically, I was able to solve this question using the centroid but without moving line OH.
Here is a quick sketch of what I did: All triangles have base of OH so you just have to show that two altitudes to line OH add up to the third. WLOG, let triangle AOH have the largest area and let A', B', C' denote altitudes from their respective points to line OH. This is euler line so G also lies on OH. Let AG instersect BC at M (which is a median) and let M' denote altitude onto OH. Note that M'M = 0.5 * AA' and since BCC'B' is trapezoid and M is midpoint, MM' = 0.5 (BB' + CC') so equate the two and we are done.
In Evan Chen's EGMO book, he says you can replace line


Reflection of (BHC) in AH
by guptaamitu1, Jun 6, 2025, 10:18 AM
Let
be a triangle with orthocentre
. Let
be the foot of altitudes of
onto the opposite sides, respectively. Consider
, the reflection of
about line
. Let line
cut
at distinct points
, and let
be the orthocenter of
. Prove that points
are concyclic.
Proposed by Mandar Kasulkar













Proposed by Mandar Kasulkar
Inspired by current year (2025)
by Rijul saini, Jun 4, 2025, 6:46 PM
Let
be an integer. We call a pair of integers
good if
Prove that the number of
good pairs is a power of
.
Proposed by Prithwijit De and Rohan Goyal



![\[0\leqslant a<k,\hspace{0.2cm} 0<b \hspace{1cm} \text{and} \hspace{1cm} (a+b)^2=ka+b\]](http://latex.artofproblemsolving.com/e/8/d/e8df562e024b8476d69fdaea15338c27bb6c4eb8.png)


Proposed by Prithwijit De and Rohan Goyal
This post has been edited 1 time. Last edited by Rijul saini, Wednesday at 7:24 PM
2025 consecutive numbers are divisible by 2026
by cuden, May 25, 2025, 4:45 PM
Good Permutations in Modulo n
by swynca, Apr 27, 2025, 2:03 PM
An integer
is called
if there exists a permutation
of the numbers
, such that:
and
have different parities for every
;
the sum
is a quadratic residue modulo
for every
.
Prove that there exist infinitely many good numbers, as well as infinitely many positive integers which are not good.












Prove that there exist infinitely many good numbers, as well as infinitely many positive integers which are not good.
This post has been edited 2 times. Last edited by swynca, Apr 27, 2025, 4:15 PM
0 points on 0 point geo
by Siddharth03, Jun 1, 2024, 6:54 PM
Let
be an equilateral triangle with incircle
. A point on
is reflected in the sides of
to obtain a new triangle
. The same point is then reflected over the sides of
to obtain another triangle
. Prove that the circumcircle of
is tangent to
.
Proposed by Siddharth Choppara









Proposed by Siddharth Choppara
Minimize Expression Over Permutation
by amuthup, Jul 12, 2022, 12:24 PM
For each integer
compute the smallest possible value of
over all permutations
of 
Proposed by Shahjalal Shohag, Bangladesh

![\[\sum_{k=1}^{n}\left\lfloor\frac{a_k}{k}\right\rfloor\]](http://latex.artofproblemsolving.com/5/6/2/562c27c7779285b6439c4087f52933a41f29ee2e.png)


Proposed by Shahjalal Shohag, Bangladesh
This post has been edited 1 time. Last edited by amuthup, Aug 12, 2022, 3:32 PM
France TST 2007
by Igor, May 16, 2007, 5:17 PM
A point
is chosen on the side
of a triangle
with
in such a way that
. The incircle of
is tangent to
and
at points
and
, respectively. Let
be the incenter of triangle
. Prove that the line
intersects the line segment
at its midpoint.














This post has been edited 1 time. Last edited by djmathman, Jun 27, 2015, 12:16 AM
Reason: changed wording to reflect english version of ISL2006
Reason: changed wording to reflect english version of ISL2006
The oldest, shortest words — "yes" and "no" — are those which require the most thought.
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