by SomeonecoolLovesMaths, May 11, 2025, 11:30 AM 
is differentiable and 
for all 
. Show that for some 
, 
.by Tricky123, May 11, 2025, 9:51 AM 
and the distribution function is 
then
and find the expression of 
by Fatoushima, May 11, 2025, 1:48 AM 
has no roots in the disc of unity.by fermion13pi, May 10, 2025, 1:58 PM ![\[
\int_0^1 \int_{x^2}^x (x^2 + y^2)^{-1/2} \, dy \, dx
\]](http://latex.artofproblemsolving.com/e/a/9/ea9f3a093b1d4c0fa39e5b6d42afa2f71dace1e0.png)
by Dattier, May 10, 2025, 1:49 PM 
a prime number, with 
and 
, 
vector space.
is a group?The oldest, shortest words — "yes" and "no" — are those which require the most thought.
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Bracket 3![$$\int_0^{1}\frac{dx}{1-\sqrt[3]{1-\sqrt{x}}}$$](http://latex.artofproblemsolving.com/d/5/e/d5e8db00985944b2eca341e37a94e34661cb5c86.png)
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![$$\int_0^{2\pi}\sqrt[4]{\cos^4(x)-\cos(2x)}dx$$](http://latex.artofproblemsolving.com/7/e/e/7eebb4a488fec702e0130a253ef87f0f6dfedb2d.png)
2. ![$$\int_0^1 \frac{x^5}{\sqrt[3]{1-x^3}}dx$$](http://latex.artofproblemsolving.com/6/0/5/605bb9d81d0ccff54a276c9f7bf1c1726c136398.png)
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2. ![$$\int_0^1 \frac{dx}{(\sqrt{x}+\sqrt[3]{x})^2}$$](http://latex.artofproblemsolving.com/6/9/8/69869c0ed754c0dfacf412ac6411742ffa164a6d.png)
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