Linetown Mayor Admits Orz
by Rijul saini, Jun 4, 2025, 6:59 PM
Having won the elections in Linetown, Turbo the Snail has become mayor, and one of the most pressing issues he needs to work on is the road network. Linetown can be represented as a configuration of
lines
in the plane, of which no two are parallel and no three are concurrent.
There is one house in Linetown for each pairwise intersection of two lines. The
lines are used as roads by the townsfolk. In the past, the roads in Linetown used to be two-way, but this often led to residents accidentally cycling back to where they started.
Turbo wants to make each of the
roads one-way such that it is impossible for any resident to start at a house, follow the roads in the correct directions, and end up back at the original house. In how many ways can Turbo achieve this?
Proposed by Archit Manas

in the plane, of which no two are parallel and no three are concurrent.
There is one house in Linetown for each pairwise intersection of two lines. The

Turbo wants to make each of the

Proposed by Archit Manas
This post has been edited 1 time. Last edited by Rijul saini, Yesterday at 7:27 PM
Beware the degeneracies!
by Rijul saini, Jun 4, 2025, 6:30 PM
Let
be real numbers satisfying
Prove that
and determine all cases of equality.
Proposed by Shantanu Nene



Proposed by Shantanu Nene
This post has been edited 1 time. Last edited by Rijul saini, Yesterday at 7:19 PM
2-var inequality
by sqing, Jun 4, 2025, 12:55 PM
Let
and
Prove that
Let
and
Prove that
Let
and
Prove that










This post has been edited 2 times. Last edited by sqing, Yesterday at 1:19 PM
Functional equation: f(xf(y)+f(x)f(y))=xf(y)+f(xy)
by Behappy0918, Jun 3, 2025, 12:24 PM
2024 IMO P6
by IndoMathXdZ, Jul 17, 2024, 12:48 PM
Let
be the set of rational numbers. A function
is called aquaesulian if the following property holds: for every
,
Show that there exists an integer
such that for any aquaesulian function
there are at most
different rational numbers of the form
for some rational number
, and find the smallest possible value of
.



![\[ f(x+f(y)) = f(x) + y \quad \text{or} \quad f(f(x)+y) = x + f(y). \]](http://latex.artofproblemsolving.com/4/0/e/40e7d033daf1bd62c2bfd5d022eeaea3f860c5b3.png)






The Bank of Oslo
by mathisreaI, Jul 13, 2022, 2:52 AM
The Bank of Oslo issues two types of coin: aluminum (denoted A) and bronze (denoted B). Marianne has
aluminum coins and
bronze coins arranged in a row in some arbitrary initial order. A chain is any subsequence of consecutive coins of the same type. Given a fixed positive integer
, Gilberty repeatedly performs the following operation: he identifies the longest chain containing the
coin from the left and moves all coins in that chain to the left end of the row. For example, if
and
, the process starting from the ordering
would be 
Find all pairs
with
such that for every initial ordering, at some moment during the process, the leftmost
coins will all be of the same type.








Find all pairs



This post has been edited 3 times. Last edited by v_Enhance, Dec 5, 2022, 4:21 AM
Reason: misspell "repeatedly"
Reason: misspell "repeatedly"
Painting Beads on Necklace
by amuthup, Jul 12, 2022, 12:24 PM
Let
be a fixed integer. There are
beads on a circular necklace. You wish to paint the beads using
colors, such that among any
consecutive beads every color appears at least once. Find the largest value of
for which this task is
possible.
Carl Schildkraut, USA






Carl Schildkraut, USA
This post has been edited 2 times. Last edited by amuthup, Jul 15, 2022, 4:06 PM
Onto the altitude'
by TheUltimate123, May 19, 2019, 8:04 PM
In triangle
, let
,
, and
denote the feet of the altitudes from
,
, and
, respectively, and let
denote the circumcenter of
. Points
and
denote the projections of
and
, respectively, onto
, and
. There exists a point
such that
and
. If
and
lies on
such that
, prove that line
bisects
.
























This post has been edited 1 time. Last edited by TheUltimate123, May 19, 2019, 8:05 PM
The oldest, shortest words — "yes" and "no" — are those which require the most thought.
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