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All the numbers to be zero after finitely many operations
orl   9
N 2 hours ago by User210790
Source: IMO Shortlist 1989, Problem 19, ILL 64
A natural number is written in each square of an $ m \times n$ chess board. The allowed move is to add an integer $ k$ to each of two adjacent numbers in such a way that non-negative numbers are obtained. (Two squares are adjacent if they have a common side.) Find a necessary and sufficient condition for it to be possible for all the numbers to be zero after finitely many operations.
9 replies
orl
Sep 18, 2008
User210790
2 hours ago
A number theory problem
super1978   2
N 2 hours ago by Tintarn
Source: Somewhere
Let $a,b,n$ be positive integers such that $\sqrt[n]{a}+\sqrt[n]{b}$ is an integer. Prove that $a,b$ are both the $n$th power of $2$ positive integers.
2 replies
super1978
May 11, 2025
Tintarn
2 hours ago
Mega angle chase
kjhgyuio   2
N 3 hours ago by Jupiterballs
Source: https://mrdrapermaths.wordpress.com/2021/01/30/filtering-with-basic-angle-facts/
........
2 replies
kjhgyuio
5 hours ago
Jupiterballs
3 hours ago
power of a point
BekzodMarupov   0
3 hours ago
Source: lemmas in olympiad geometry
Epsilon 1.3. Let ABC be a triangle and let D, E, F be the feet of the altitudes, with D on BC, E on CA, and F on AB. Let the parallel through D to EF meet AB at X and AC at Y. Let T be the intersection of EF with BC and let M be the midpoint of side BC. Prove that the points T, M, X, Y are concyclic.
0 replies
BekzodMarupov
3 hours ago
0 replies
Interesting inequalities
sqing   1
N 4 hours ago by sqing
Source: Own
Let $a,b,c \geq 0 $ and $ab+bc+ca- abc =3.$ Show that
$$a+k(b+c)\geq 2\sqrt{3 k}$$Where $ k\geq 1. $
Let $a,b,c \geq 0 $ and $2(ab+bc+ca)- abc =31.$ Show that
$$a+k(b+c)\geq \sqrt{62k}$$Where $ k\geq 1. $
1 reply
1 viewing
sqing
4 hours ago
sqing
4 hours ago
euler function
mathsearcher   0
4 hours ago
Prove that there exists infinitely many positive integers n such that
ϕ(n) | n+1
0 replies
mathsearcher
4 hours ago
0 replies
Simple but hard
Lukariman   1
N 5 hours ago by Giant_PT
Given triangle ABC. Outside the triangle, construct rectangles ACDE and BCFG with equal areas. Let M be the midpoint of DF. Prove that CM passes through the center of the circle circumscribing triangle ABC.
1 reply
Lukariman
6 hours ago
Giant_PT
5 hours ago
Floor function and coprime
mofumofu   13
N 5 hours ago by Thapakazi
Source: 2018 China TST 2 Day 2 Q4
Let $k, M$ be positive integers such that $k-1$ is not squarefree. Prove that there exist a positive real $\alpha$, such that $\lfloor \alpha\cdot k^n \rfloor$ and $M$ are coprime for any positive integer $n$.
13 replies
1 viewing
mofumofu
Jan 9, 2018
Thapakazi
5 hours ago
Interesting inequalities
sqing   2
N 5 hours ago by sqing
Source: Own
Let $a,b,c \geq 0 $ and $ abc+2(ab+bc+ca) =32.$ Show that
$$ka+b+c\geq 8\sqrt k-2k$$Where $0<k\leq 4. $
$$ka+b+c\geq 8 $$Where $ k\geq 4. $
$$a+b+c\geq 6$$$$2a+b+c\geq 8\sqrt 2-4$$
2 replies
sqing
Yesterday at 2:51 PM
sqing
5 hours ago
RMM 2013 Problem 3
dr_Civot   79
N 5 hours ago by Ilikeminecraft
Let $ABCD$ be a quadrilateral inscribed in a circle $\omega$. The lines $AB$ and $CD$ meet at $P$, the lines $AD$ and $BC$ meet at $Q$, and the diagonals $AC$ and $BD$ meet at $R$. Let $M$ be the midpoint of the segment $PQ$, and let $K$ be the common point of the segment $MR$ and the circle $\omega$. Prove that the circumcircle of the triangle $KPQ$ and $\omega$ are tangent to one another.
79 replies
dr_Civot
Mar 2, 2013
Ilikeminecraft
5 hours ago
geometric inequality
junior2001   4
N May 21, 2015 by LeVietAn
Let $ ABCD $ be the convex quadrilateral.Let internal angle bisectors of $ A $ and $ D $ meet at $ K $, and let internal angle bisectors of $ B $ and $ C $ meet at $ L $.Prove that $ 2KL \ge |AB-BC+CD-DA| $.
4 replies
junior2001
Apr 24, 2015
LeVietAn
May 21, 2015
geometric inequality
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junior2001
333 posts
#1 • 1 Y
Y by Adventure10
Let $ ABCD $ be the convex quadrilateral.Let internal angle bisectors of $ A $ and $ D $ meet at $ K $, and let internal angle bisectors of $ B $ and $ C $ meet at $ L $.Prove that $ 2KL \ge |AB-BC+CD-DA| $.
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junior2001
333 posts
#2 • 2 Y
Y by Adventure10, Mango247
Any solution?
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junior2001
333 posts
#3 • 1 Y
Y by Adventure10
Any solution ? Please help me
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tranquanghuy7198
253 posts
#4 • 3 Y
Y by tahanguyen98, Adventure10, Mango247
You can easily get it yourself, but this is my solution:
$AD\cap{BC} = S$, $E, F$ is the projections of $L, K$ on $AD$
We have:
$2KL$$\geq$$2FE = $$\mid$$2SF-2SE$$\mid$$ = $$\mid$$(SC+SD-CD)-(SA+SB+AB)$$\mid$ = $\mid$$AD+BC-AB-CD$$\mid$
Q.E.D
Attachments:
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LeVietAn
375 posts
#5 • 3 Y
Y by kiyoras_2001, Adventure10, Mango247
You can see:
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