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The Chile Awkward Party
vicentev   0
28 minutes ago
Source: TST IMO CHILE 2025
At a meeting, there are \( N \) people who do not know each other. Prove that it is possible to introduce them in such a way that no three of them have the same number of acquaintances.
0 replies
vicentev
28 minutes ago
0 replies
Sharygin CR P20
TheDarkPrince   37
N 32 minutes ago by E50
Source: Sharygin 2018
Let the incircle of a nonisosceles triangle $ABC$ touch $AB$, $AC$ and $BC$ at points $D$, $E$ and $F$ respectively. The corresponding excircle touches the side $BC$ at point $N$. Let $T$ be the common point of $AN$ and the incircle, closest to $N$, and $K$ be the common point of $DE$ and $FT$. Prove that $AK||BC$.
37 replies
TheDarkPrince
Apr 4, 2018
E50
32 minutes ago
Fibonacci sequence and primes
vicentev   0
32 minutes ago
Source: TST IMO CHILE 2025
Let \( u_n \) be the \( n \)-th term of the Fibonacci sequence (where \( u_1 = u_2 = 1 \) and \( u_{n+1} = u_n + u_{n-1} \) for \( n \geq 2 \)). For each prime \( p \), let \( n(p) \) be the smallest integer \( n \) such that \( u_n \) is divisible by \( p \). Find the smallest possible value of \( p - n(p) \).
0 replies
vicentev
32 minutes ago
0 replies
Gheorghe Țițeica 2025 Grade 7 P3
AndreiVila   1
N 33 minutes ago by Rainbow1971
Source: Gheorghe Țițeica 2025
Out of all the nondegenerate triangles with positive integer sides and perimeter $100$, find the one with the smallest area.
1 reply
AndreiVila
Yesterday at 8:41 PM
Rainbow1971
33 minutes ago
functional equations
sefatod628   6
N 33 minutes ago by pco
Source: Oral ENS
Hello guys, here is a fun functional equation !
Find all functions from $\mathbb{R^*_+}$ to $\mathbb{R^*_+}$ such that for all $x$ : $$f(f(x))=-f(x)+6x$$
Hint : Click to reveal hidden text
6 replies
sefatod628
Oct 28, 2024
pco
33 minutes ago
A number theory about divisors which no one fully solved at the contest
nAalniaOMliO   19
N 35 minutes ago by Bluecloud123
Source: Belarusian national olympiad 2024
Let's call a pair of positive integers $(k,n)$ interesting if $n$ is composite and for every divisor $d<n$ of $n$ at least one of $d-k$ and $d+k$ is also a divisor of $n$
Find the number of interesting pairs $(k,n)$ with $k \leq 100$
M. Karpuk
19 replies
+1 w
nAalniaOMliO
Jul 24, 2024
Bluecloud123
35 minutes ago
hard problem
Cobedangiu   3
N an hour ago by lyllyl
problem
3 replies
Cobedangiu
2 hours ago
lyllyl
an hour ago
Gheorghe Țițeica 2025 Grade 9 P1
AndreiVila   1
N an hour ago by AlgebraKing
Source: Gheorghe Țițeica 2025
Let there be $2n+1$ distinct points on a circle. Consider the set of distances between any two out of the $2n+1$ points. What is the smallest size of this set?

Radu Bumbăcea
1 reply
AndreiVila
Yesterday at 9:06 PM
AlgebraKing
an hour ago
Straightforward NT
TheMathBob   5
N an hour ago by Avron
Source: Polish MO Finals P1 2023
Given a sequence of positive integers $a_1, a_2, a_3, \ldots$ such that for any positive integers $k$, $l$ we have $k+l ~ | ~ a_k + a_l$. Prove that for all positive integers $k > l$, $a_k - a_l$ is divisible by $k-l$.
5 replies
TheMathBob
Mar 29, 2023
Avron
an hour ago
2025 TST 22
EthanWYX2009   0
an hour ago
Source: 2025 TST 22
Let \( A \) be a set of 2025 positive real numbers. For a subset \( T \subseteq A \), define \( M_T \) as the median of \( T \) when all elements of \( T \) are arranged in increasing order, with the convention that \( M_\emptyset = 0 \). Define
\[
P(A) = \sum_{\substack{T \subseteq A \\ |T| \text{ odd}}} M_T, \quad Q(A) = \sum_{\substack{T \subseteq A \\ |T| \text{ even}}} M_T.
\]Find the smallest real number \( C \) such that for any set \( A \) of 2025 positive real numbers, the following inequality holds:
\[
P(A) - Q(A) \leq C \cdot \max(A),
\]where \(\max(A)\) denotes the largest element in \( A \).
0 replies
+2 w
EthanWYX2009
an hour ago
0 replies
The incircle problem
danil_e   1
N Dec 1, 2023 by ancamagelqueme
Given triangle \(ABC\) inscribed in circle \((O)\) and circumscribed about circle \((I)\). A circle passing through \(B\) and \(C\) is tangent to \((I)\) at \(N_a\) and intersects \(AB\) and \(AC\) at \(A_c\) and \(A_b\) respectively. Similarly, define \(B_c, B_a, N_b\) and \(C_b, C_a, N_c\) correspondingly. Let \(XYZ\) be the triangle formed by the radical axis of circles \((N_aBC)\), \((N_bCA)\), \((N_cBA)\) (as shown in the figure); \(MNP\) is the triangle formed by the intersection of lines \(A_cC_a\), \(B_cC_b\), \(A_bB_a\) (as shown in the figure).

a) Prove that: Triangle \(XYZ\) and triangle \(MNP\) are in perspective axially.
b) Let \(S\) be the point of concurrence of \(XM\), \(YN\), \(ZP\). Prove that: \(S\), \(I\), \(O\) are collinear.
1 reply
danil_e
Dec 1, 2023
ancamagelqueme
Dec 1, 2023
The incircle problem
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danil_e
25 posts
#1
Y by
Given triangle \(ABC\) inscribed in circle \((O)\) and circumscribed about circle \((I)\). A circle passing through \(B\) and \(C\) is tangent to \((I)\) at \(N_a\) and intersects \(AB\) and \(AC\) at \(A_c\) and \(A_b\) respectively. Similarly, define \(B_c, B_a, N_b\) and \(C_b, C_a, N_c\) correspondingly. Let \(XYZ\) be the triangle formed by the radical axis of circles \((N_aBC)\), \((N_bCA)\), \((N_cBA)\) (as shown in the figure); \(MNP\) is the triangle formed by the intersection of lines \(A_cC_a\), \(B_cC_b\), \(A_bB_a\) (as shown in the figure).

a) Prove that: Triangle \(XYZ\) and triangle \(MNP\) are in perspective axially.
b) Let \(S\) be the point of concurrence of \(XM\), \(YN\), \(ZP\). Prove that: \(S\), \(I\), \(O\) are collinear.
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ancamagelqueme
104 posts
#2
Y by
The point $S$ is NOT aligned with $I=X_1$ and $O=X_3$. If it is on the line $X_{57}X_{2346}$.

The barycentric coordinates of $S$, with respect to $ABC$, are given by the triangle center function

f(a,b,c)= a (a+b-c) (a-b+c)(a(b+c)-(b-c)^2)((b-c)^6 (b+c)^2 (b^2-3 b c+c^2)-2 (b-c)^4 (4 b^5-b^4 c-11 b^3 c^2-11 b^2 c^3-b c^4+4 c^5) a+(b-c)^2 (27 b^6+4 b^5 c-39 b^4 c^2-112 b^3 c^3-39 b^2 c^4+4 b c^5+27 c^6) a^2-2 (b-c)^2 (24 b^5+55 b^4 c+97 b^3 c^2+97 b^2 c^3+55 b c^4+24 c^5) a^3+2 (21 b^6+56 b^5 c+141 b^4 c^2+140 b^3 c^3+141 b^2 c^4+56 b c^5+21 c^6) a^4-2 b c (49 b^3+167 b^2 c+167 b c^2+49 c^3) a^5-2 (21 b^4+7 b^3 c-34 b^2 c^2+7 b c^3+21 c^4) a^6+2 (24 b^3+35 b^2 c+35 b c^2+24 c^3) a^7+(-27 b^2-41 b c-27 c^2) a^8+8 (b+c) a^9-a^10)
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