1952 AHSME Problems/Problem 29
Problem
In a circle of radius units, and are perpendicular diameters. A chord cutting at is units long. The diameter is divided into two segments whose dimensions are:
Solution
Let the intersection of and be , be the center of the circle, and . By power of a point on , we have is a right triangle, so we also know that , thus It follows that .
, so the answer is .
See also
1952 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 28 |
Followed by Problem 30 | |
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