1961 AHSME Problems/Problem 16
Problem
An altitude of a triangle is increased by a length . How much must be taken from the corresponding base so that the area of the new triangle is one-half that of the original triangle?
Solution
Let be the value reduced from the base. Using the variables from the problem, the equation to solve is Dividing both sides by and results in The right side can be written as a single fraction by giving a common denominator. The answer is .
See Also
1961 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 15 |
Followed by Problem 17 | |
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