1961 AHSME Problems/Problem 19
Problem
Consider the graphs of and . We may say that:
Solution
Substitute into the other equation. Using a logarithm property, Subtract both sides by to get Thus, . Since both and are functions, there is only one corresponding y-value, so the answer is .
See Also
1961 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 18 |
Followed by Problem 20 | |
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