1971 AHSME Problems/Problem 25
Problem
A teen age boy wrote his own age after his father's. From this new four place number, he subtracted the absolute value of the difference of their ages to get . The sum of their ages was
Solution
Because the father's age is a two digit number, we know that the father's age must be so that the second two digits of the original number can be a number in the teens. Let the son's age be . We know that the original number is , and the positive difference between their ages is . Thus, we have the equation , which yields . Thus, the sum of the two ages is .
See Also
1971 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 24 |
Followed by Problem 26 | |
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