1971 AHSME Problems/Problem 8
Problem
The solution set of is the set of all values of such that
Solution
We are solving the inequality This can be factored as
The graph of this inequality is a parabola facing upwards, so the interval between the roots satisfies the equation. This interval, , is answer .
-edited by coolmath34
See Also
1971 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 7 |
Followed by Problem 9 | |
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