1974 AHSME Problems/Problem 2
Problem
Let and be such that and , . Then equals
Solution
Notice that and are the distinct solutions to the quadratic . By Vieta, the sum of the roots of this quadratic is the negation of the coefficient of the linear term divided by the coefficient of the quadratic term, so in this case .
See Also
1974 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
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