1974 AHSME Problems/Problem 25
Problem
In parallelogram of the accompanying diagram, line is drawn bisecting at and meeting (extended) at . From vertex , line is drawn bisecting side at and meeting (extended) at . Lines and meet at . If the area of parallelogram is , then the area of the triangle is equal to
Solution
Note that
Also, note that is a parallelogram, and so .
Therefore, .
See Also
1974 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 24 |
Followed by Problem 26 | |
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