1983 AHSME Problems/Problem 18
Contents
[hide]Problem
Let be a polynomial function such that, for all real , . For all real is
Solution
Let . Then , so we can write the given equation as Then substituting for , we get The answer is therefore .
Solution 2
Let We have that
Thus, we have
If we plug in we have
See Also
1983 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 17 |
Followed by Problem 19 | |
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