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1992 AJHSME Problems/Problem 14

Problem

When four gallons are added to a tank that is one-third full, the tank is then one-half full. The capacity of the tank in gallons is

$\text{(A)}\ 8 \qquad \text{(B)}\ 12 \qquad \text{(C)}\ 20 \qquad \text{(D)}\ 24 \qquad \text{(E)}\ 48$

Solution

Four gallons is $\frac{1}{2}-\frac{1}{3}= \frac{1}{6}$. Thus, capacity of the tank in gallons is $6 \times 4= \boxed{\text{(D)}\ 24}$.

See Also

1992 AJHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 13
Followed by
Problem 15
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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