1993 AJHSME Problems/Problem 14
Problem
The nine squares in the table shown are to be filled so that every row and every column contains each of the numbers . Then
Solution
The square connected both to 1 and 2 cannot be the same as either of them, so must be 3.
The last square in the top row cannot be either 1 or 3, so it must be 2.
The other two squares in the rightmost column with A and B cannot be two, so they must be 1 and 3 and therefore have a sum of .
See Also
1993 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 13 |
Followed by Problem 15 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.