2005 AMC 10A Problems/Problem 18
Contents
[hide]Problem
Team A and team B play a series. The first team to win three games wins the series. Before each game, each team is equally likely to win each game, there are no ties, and the outcomes of the individual games are independent. If it turns out that team B won the second game and team A won the series, what is the conditional probability that team B won the first game?
Solution
There are at most games played.
If team won the first two games, team would need to win the next three games. So the only possible order of wins is .
If team won the first game, and team won the second game, the possible order of wins are: and , where denotes that the th game wasn't played.
There is possibility where team wins the first game and total possibilities when team wins the series and team wins the second game. Note that the fourth possibility occurs twice as often as the others because it is dependent on the outcome of games instead of , so we put over total possibilities. The desired probability is then .
Note
The original final problem was poorly worded, since the problem directly stated that the answer is .
The problem should say "what fraction of possible sets of game outcomes have winning the first game?" or "Given the observed results, what is the conditional probability that won the first game?"
(Many problems in probability are poorly worded.)
See Also
2005 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 17 |
Followed by Problem 19 | |
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