2005 AMC 10A Problems/Problem 18
Team A and team B play a series. The first team to win three games wins the series. Each team is equally likely to win each game, there are no ties, and the outcomes of the individual games are independent. If team B wins the second game and team A wins the series, what is the probability that team B wins the first game?
There are at most games played.
If team B won the first two games, team A would need to win the next three games. So the only possible order of wins is BBAAA.
If team A won the first game, and team B won the second game, the possible order of wins are: ABBAA, ABABA, and ABAAX, where X denotes that the 5th game wasn't played.
There is possibility where team B wins the first game and total possibilities when team A wins the series and team B wins the second game. Note that the fourth possibility (ABAAX) occurs just as often as the others, so we put over total possibilities. The desired probability is then
The fourth possibility (ABAAX) simply counts as 1 case, and it does not occur twice as often as the others because we are given the information that team A will win the series after winning three games by the problem.
We have 4 cases, out of which only 1 (BBAAA) is desired. Thus, our answer is -Flames
edited by mobius247
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