2005 AMC 10A Problems/Problem 21
Contents
[hide]Problem
For how many positive integers does evenly divide from ?
Solution
If evenly divides , then is an integer.
Since we may substitute the RHS in the above fraction. So the problem asks us for how many positive integers is an integer, or equivalently when for a positive integer .
is an integer when is a factor of .
The factors of are and , so the possible values of are and .
But since isn't a positive integer, only and are the possible values of . Therefore the number of possible values of is .
Video Solution
CHECK OUT Video Solution: https://youtu.be/WRv86DHa3zY
See also
2005 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 20 |
Followed by Problem 22 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.