2012 AMC 8 Problems/Problem 1

Problem

Rachelle uses 3 pounds of meat to make 8 hamburgers for her family. How many pounds of meat does she need to make 24 hamburgers for a neighbourhood picnic?

$\textbf{(A)}\hspace{.05in}6 \qquad \textbf{(B)}\hspace{.05in}6\dfrac23 \qquad \textbf{(C)}\hspace{.05in}7\dfrac12 \qquad \textbf{(D)}\hspace{.05in}8 \qquad \textbf{(E)}\hspace{.05in}9$

Solution 1

Since Rachelle uses $3$ pounds of meat to make $8$ hamburgers, she uses $\frac{3}{8}$ pounds of meat to make one hamburger. She'll need 24 times that amount of meat for 24 hamburgers, or $\frac{3}{8} \cdot 24 = \boxed{\textbf{(E)}\ 9}$ .

Solution 2

We have the proportion $\frac{3}{8}$ = $\frac{x}{24}$ . To solve for $x$ , multiply the left side of the equation by $\frac{3}{3}$ . We find that $x=9$ . ~Andrew_Lu

Video Solution

https://youtu.be/GG61DsRqoo4 ~savannahsolver

2012 AMC 8 (Problems • Answer Key • Resources)
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All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

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2012 AMC 8 Problems/Problem 1

Contents

Problem

Solution 1

Solution 2

Video Solution

See Also