2012 AMC 8 Problems/Problem 25
Problem
A square with area is inscribed in a square with area , with each vertex of the smaller square on a side of the larger square. A vertex of the smaller square divides a side of the larger square into two segments, one of length , and the other of length . What is the value of ?
Solution 1
The total area of the four congruent triangles formed by the squares is . Therefore, the area of one of these triangles is . The height of one of these triangles is and the base is . Using the formula for area of the triangle, we have . Multiply by on both sides to find that the value of is .
Video Solution 2
https://youtu.be/MhxGq1sSA6U ~savannahsolver
Video Solution by OmegaLearn
https://youtu.be/j3QSD5eDpzU?t=2
~ pi_is_3.14
See Also
2012 AMC 8 (Problems • Answer Key • Resources) | ||
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