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• 2017 AMC 10A Problems/Problem 18
  Solution by ktong
  3 KB (497 words) - 18:06, 19 December 2023
• 2018 AMC 10A Problems/Problem 21
  Solution by ktong
  10 KB (1,671 words) - 20:03, 11 October 2024
• 2018 AIME II Problems/Problem 5
  Solution by ktong
  11 KB (2,077 words) - 19:15, 12 January 2024
• 2018 AIME II Problems/Problem 7
  ~Solution by ktong
  5 KB (841 words) - 02:26, 23 December 2023
• 2018 AIME II Problems/Problem 9
  Solution by ktong
  5 KB (782 words) - 03:49, 27 August 2024
• 2019 AIME II Problems/Problem 7
  -ktong
  7 KB (1,053 words) - 13:58, 14 January 2024
• 2019 AIME II Problems/Problem 10
  ...{135}{2}}{\frac{7}{8}}=\frac{540}{7}\implies p+q=540+7=\boxed{547}</cmath>-ktong
  8 KB (1,172 words) - 17:21, 8 August 2024
• 2019 AIME II Problems/Problem 14
  ...of <math>n</math>. Hence, the answer is <math>24+47=\boxed{071}</math>. - ktong
  8 KB (1,317 words) - 08:36, 22 July 2024
• 2019 AIME II Problems/Problem 6
  -ktong
  7 KB (1,165 words) - 09:09, 5 April 2024
• 2020 AIME I Problems/Problem 7
  so the desired answer is <math>2+7+13+17+19+23=\boxed{081}</math> ~ktong
  7 KB (1,023 words) - 22:56, 13 February 2023
• 2020 AIME I Problems/Problem 14
  Therefore, the solution is <math>49+36=\boxed{085}</math> ~ktong
  10 KB (1,819 words) - 18:34, 17 September 2023
• 2020 AMC 12A Problems/Problem 25
  ~ktong
  9 KB (1,541 words) - 16:13, 21 July 2022