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• 1980 USAMO Problems/Problem 2
  ~Lopkiloinm (corrected by integralarefun)
  2 KB (405 words) - 19:04, 9 August 2023
• 2012 AMC 8 Problems/Problem 20
  ...math>\boxed{\textbf{(B)}\ \frac{5}{19}<\frac{7}{21}<\frac{9}{23}}</math>. ~lopkiloinm
  4 KB (513 words) - 18:34, 20 January 2024
• 1952 AHSME Problems/Problem 49
  ...textbf{(C) }\frac{1}{7}[ABC]}</cmath> ~many credits to the first solution ~Lopkiloinm ...le factor is thus <math>\frac{1}{\sqrt{7}}</math> giving us an answer of: ~Lopkiloinm <cmath>\boxed{\textbf{(C) }\frac{1}{7}[ABC]}</cmath> (Note: the presence of
  7 KB (1,136 words) - 10:01, 23 December 2023
• 2016 AIME I Problems/Problem 6
  ...rac{10}{3}</math>, giving us our desired answer <math>\boxed{013}</math>. ~Lopkiloinm
  14 KB (2,397 words) - 20:04, 27 August 2023
• 2020 AIME II Problems/Problem 1
  ~Lopkiloinm
  2 KB (346 words) - 13:59, 25 February 2024
• 2020 AMC 12A Problems/Problem 9
  ~MRENTHUSIASM ~lopkiloinm ~hi13 ~annabelle0913 ~codecow
  4 KB (615 words) - 04:07, 8 July 2022
• 2020 AMC 12A Problems/Problem 12
  ...ept is therefore <math>20-\frac{20}{4} = \boxed{\textbf{(B) } 15.}</math> ~lopkiloinm ~ShawnX (diagram)
  7 KB (1,145 words) - 20:27, 5 November 2023
• 2020 AMC 12A Problems/Problem 15
  ~lopkiloinm ~MRENTHUSIASM
  4 KB (696 words) - 12:38, 13 September 2021
• 2020 AMC 12A Problems/Problem 13
  ...means that <math>b</math> must equal <math>\boxed{\textbf{(B) } 3.}</math>~lopkiloinm
  4 KB (639 words) - 18:48, 12 September 2023
• 2020 AIME II Problems/Problem 4
  ...ath>P(21,-3)</math>. Our answer is then <math>90+21-3=\boxed{108}</math>. ~Lopkiloinm & samrocksnature
  10 KB (1,542 words) - 13:29, 19 January 2024
• 2020 AIME II Problems/Problem 13
  ~Lopkiloinm
  13 KB (2,197 words) - 23:00, 8 January 2024
• 2021 AMC 12A Problems/Problem 16
  ...ke the only number close to it, it is answer <math>\boxed{(C) 142}</math> ~Lopkiloinm
  5 KB (686 words) - 22:56, 16 October 2023
• 1972 AHSME Problems/Problem 5
  ...answer is therefore <math>\boxed{\textbf{(A) } 3^{1/3},\ 2^{1/2}}.</math> ~lopkiloinm
  702 bytes (84 words) - 02:01, 7 November 2020
• 1972 AHSME Problems/Problem 3
  ...>-1</math> which makes the answer <cmath>\boxed{\textbf{(C) }-1}.</cmath> ~lopkiloinm
  489 bytes (74 words) - 01:54, 7 November 2020
• 1972 AHSME Problems/Problem 4
  ...cs in mind, the answer is simply <math>2^3=\boxed{\textbf{(D) }8}.</math> ~lopkiloinm
  642 bytes (92 words) - 02:41, 7 November 2020
• 1972 AHSME Problems/Problem 16
  ...7/4</math>. Their sum is <math>\boxed{\textbf{(B) }11\frac{1}{4}}</math>. ~lopkiloinm
  2 KB (370 words) - 13:44, 4 April 2024
• 1972 AHSME Problems/Problem 17
  ...probability is therefore <math>\boxed{\textbf{(E) }\frac{2}{x+1}}.</math> ~lopkiloinm
  619 bytes (101 words) - 03:13, 7 November 2020
• 1972 AHSME Problems/Problem 34
  ...already. The answer is thus <math>1+16+25=\boxed{\textbf{(A) }42}.</math> ~lopkiloinm
  917 bytes (153 words) - 04:17, 7 November 2020
• 2020 USAMO Problems/Problem 4
  <cmath>\boxed{N=197}.</cmath>~Lopkiloinm
  5 KB (933 words) - 12:40, 18 June 2023
• 2021 AMC 12B Problems/Problem 12
  ...because it is multiple choice and you don't have to do critical thinking. ~Lopkiloinm
  5 KB (878 words) - 09:56, 20 May 2023

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