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• 2019 AIME II Problems/Problem 15
  and the answer is <math>560 + 14 = \boxed{574}</math>. ~rocketsri
  7 KB (1,115 words) - 02:11, 7 January 2024
• 2020 AMC 12A Problems/Problem 12
  ~rocketsri (minor error corrected by kn07)
  7 KB (1,145 words) - 19:27, 5 November 2023
• 2021 AIME I Problems/Problem 1
  ~rocketsri
  5 KB (780 words) - 23:58, 22 August 2022
• 2020 CIME I Problems/Problem 7
  ...stem of congruences, we get <math>p \equiv \boxed{312}\pmod{1000}</math>. ~rocketsri (based off of official solution)
  2 KB (282 words) - 11:05, 2 February 2021
• 2020 CIME I Problems/Problem 10
  ...10130 + 288 = 10418</math>, so the remainder is <math>\boxed{418}</math>. ~rocketsri
  1 KB (239 words) - 10:47, 2 February 2021
• 2021 AMC 12A Problems/Problem 9
  ~rocketsri
  8 KB (1,189 words) - 02:09, 31 October 2024
• 2021 AMC 12A Problems/Problem 23
  ...orresponding to choice <math>\boxed{\textbf{(D)} ~\frac{25}{32}}</math>. ~rocketsri
  17 KB (2,801 words) - 14:35, 30 August 2024
• 2021 AMC 10B Problems/Problem 21
  ...{5}{6} = 2</math>, so our answer is <math>\boxed{\textbf{(A)} ~2}</math>. ~rocketsri
  8 KB (1,252 words) - 23:15, 24 October 2024
• 2021 AMC 10B Problems/Problem 23
  ~rocketsri
  6 KB (865 words) - 21:11, 2 November 2024
• 2021 AMC 12B Problems/Problem 20
  ~ rohan.sp ~rocketsri
  8 KB (1,315 words) - 10:43, 24 October 2023
• 2021 AIME II Problems/Problem 13
  ~rocketsri
  16 KB (2,240 words) - 22:16, 26 January 2024