Difference between revisions of "2021 AIME II Problems/Problem 10"
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Revision as of 10:12, 23 March 2021
Problem
Two spheres with radii and one sphere with radius
are each externally tangent to the other two spheres and to two different planes
and
. The intersection of planes
and
is the line
. The distance from line
to the point where the sphere with radius
is tangent to plane
is
, where
and
are relatively prime positive integers. Find
.
Solution
The centers of the three spheres form a 49-49-72 triangle. Consider the points at which the plane is tangent to the two bigger spheres; the line segment connecting these two points should be parallel to the 72 side of this triangle. Take its midpoint , which is 36 away from the midpoint of the 72 side
, and connect these two midpoints.
Now consider the point at which the plane is tangent to the small sphere, and connect with the small sphere's tangent point
. Extend
through B until it hits the ray from
through the center of the small sphere (convince yourself that these two intersect). Call this intersection
, the center of the small sphere
, we want to find
.
By Pythagorus AC= , and we know
. We know that
must be parallel, using ratios we realize that
. Apply Pythagorean theorem on triangle BCD;
, so 312 + 23 =
-Ross Gao
-ARCTICTURN made slight edit to show the solution
See also
2021 AIME II (Problems • Answer Key • Resources) | ||
Preceded by Problem 9 |
Followed by Problem 11 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All AIME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.