Difference between revisions of "2011 AMC 8 Problems/Problem 20"
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==Video Solution== | ==Video Solution== | ||
https://youtu.be/SiP_0xLVFSo ~David | https://youtu.be/SiP_0xLVFSo ~David | ||
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==Video Solution by WhyMath== | ==Video Solution by WhyMath== |
Revision as of 11:30, 15 July 2024
Contents
Problem
Quadrilateral is a trapezoid,
,
,
, and the altitude is
. What is the area of the trapezoid?
Solution
If you draw altitudes from and
to
the trapezoid will be divided into two right triangles and a rectangle. You can find the values of
and
with the Pythagorean theorem.
is a rectangle so
The area of the trapezoid is
Video Solution by OmegaLearn
https://youtu.be/51K3uCzntWs?t=2521
~ pi_is_3.14
Video Solution
https://youtu.be/SiP_0xLVFSo ~David
Video Solution by WhyMath
~savannahsolver
Video Solution by SpreadTheMathLove
https://www.youtube.com/watch?v=mYn6tNxrWBU
See Also
2011 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 19 |
Followed by Problem 21 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.