Difference between revisions of "1989 AJHSME Problems"
5849206328x (talk | contribs) |
5849206328x (talk | contribs) |
||
Line 1: | Line 1: | ||
== Problem 1 == | == Problem 1 == | ||
+ | |||
+ | <math>(1+11+21+31+41)+(9+19+29+39+49)=</math> | ||
+ | |||
+ | <math>\text{(A)}\ 150 \qquad \text{(B)}\ 199 \qquad \text{(C)}\ 200 \qquad \text{(D)}\ 249 \qquad \text{(E)}\ 250</math> | ||
[[1989 AJHSME Problems/Problem 1|Solution]] | [[1989 AJHSME Problems/Problem 1|Solution]] | ||
== Problem 2 == | == Problem 2 == | ||
+ | |||
+ | <math>\frac{2}{10}+\frac{4}{100}+\frac{6}{1000} =</math> | ||
+ | |||
+ | <math>\text{(A)}\ .012 \qquad \text{(B)}\ .0246 \qquad \text{(C)}\ .12 \qquad \text{(D)}\ .246 \qquad \text{(E)}\ 246</math> | ||
[[1989 AJHSME Problems/Problem 2|Solution]] | [[1989 AJHSME Problems/Problem 2|Solution]] | ||
== Problem 3 == | == Problem 3 == | ||
+ | |||
+ | Which of the following numbers is the largest? | ||
+ | |||
+ | <math>\text{(A)}\ .99 \qquad \text{(B)}\ .9099 \qquad \text{(C)}\ .9 \qquad \text{(D)}\ .909 \qquad \text{(E)}\ .9009</math> | ||
[[1989 AJHSME Problems/Problem 3|Solution]] | [[1989 AJHSME Problems/Problem 3|Solution]] | ||
== Problem 4 == | == Problem 4 == | ||
+ | |||
+ | Estimate to determine which of the following numbers is closest to <math>\frac{401}{.205}</math>. | ||
+ | |||
+ | <math>\text{(A)}\ .2 \qquad \text{(B)}\ 2 \qquad \text{(C)}\ 20 \qquad \text{(D)}\ 200 \qquad \text{(E)}\ 2000</math> | ||
[[1989 AJHSME Problems/Problem 4|Solution]] | [[1989 AJHSME Problems/Problem 4|Solution]] | ||
== Problem 5 == | == Problem 5 == | ||
+ | |||
+ | <math>-15+9\times (6\div 3) =</math> | ||
+ | |||
+ | <math>\text{(A)}\ -48 \qquad \text{(B)}\ -12 \qquad \text{(C)}\ -3 \qquad \text{(D)}\ 3 \qquad \text{(E)}\ 12</math> | ||
[[1989 AJHSME Problems/Problem 5|Solution]] | [[1989 AJHSME Problems/Problem 5|Solution]] | ||
Line 24: | Line 44: | ||
== Problem 7 == | == Problem 7 == | ||
+ | |||
+ | If the value of <math>20</math> quarters and <math>10</math> dimes equals the value of <math>10</math> quarters and <math>n</math> dimes, then <math>n=</math> | ||
+ | |||
+ | <math>\text{(A)}\ 10 \qquad \text{(B)}\ 20 \qquad \text{(C)}\ 30 \qquad \text{(D)}\ 35 \qquad \text{(E)}\ 45</math> | ||
[[1989 AJHSME Problems/Problem 7|Solution]] | [[1989 AJHSME Problems/Problem 7|Solution]] | ||
== Problem 8 == | == Problem 8 == | ||
+ | |||
+ | <math>(2\times 3\times 4)\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\right) =</math> | ||
+ | |||
+ | <math>\text{(A)}\ 1 \qquad \text{(B)}\ 3 \qquad \text{(C)}\ 9 \qquad \text{(D)}\ 24 \qquad \text{(E)}\ 26</math> | ||
[[1989 AJHSME Problems/Problem 8|Solution]] | [[1989 AJHSME Problems/Problem 8|Solution]] | ||
== Problem 9 == | == Problem 9 == | ||
+ | |||
+ | There are <math>2</math> boys for every <math>3</math> girls in Ms. Johnson's math class. If there are <math>30</math> students in her class, what percent of them are boys? | ||
+ | |||
+ | <math>\text{(A)}\ 12\% \qquad \text{(B)}\ 20\% \qquad \text{(C)}\ 40\% \qquad \text{(D)}\ 60\% \qquad \text{(E)}\ 66\frac{2}{3}\% </math> | ||
[[1989 AJHSME Problems/Problem 9|Solution]] | [[1989 AJHSME Problems/Problem 9|Solution]] | ||
== Problem 10 == | == Problem 10 == | ||
+ | |||
+ | What is the number of degrees in the smaller angle between the hour hand and the minute hand on a clock that reads seven o'clock? | ||
+ | |||
+ | <math>\text{(A)}\ 50^\circ \qquad \text{(B)}\ 120^\circ \qquad \text{(C)}\ 135^\circ \qquad \text{(D)}\ 150^\circ \qquad \text{(E)}\ 165^\circ</math> | ||
[[1989 AJHSME Problems/Problem 10|Solution]] | [[1989 AJHSME Problems/Problem 10|Solution]] | ||
Line 44: | Line 80: | ||
== Problem 12 == | == Problem 12 == | ||
+ | |||
+ | <math>\frac{1-\frac{1}{3}}{1-\frac{1}{2}} =</math> | ||
+ | |||
+ | <math>\text{(A)}\ \frac{1}{3} \qquad \text{(B)}\ \frac{2}{3} \qquad \text{(C)}\ \frac{3}{4} \qquad \text{(D)}\ \frac{3}{2} \qquad \text{(E)}\ \frac{4}{3}</math> | ||
[[1989 AJHSME Problems/Problem 12|Solution]] | [[1989 AJHSME Problems/Problem 12|Solution]] | ||
== Problem 13 == | == Problem 13 == | ||
+ | |||
+ | <math>\frac{9}{7\times 53} =</math> | ||
+ | |||
+ | <math>\text{(A)}\ \frac{.9}{.7\times 53} \qquad \text{(B)}\ \frac{.9}{.7\times .53} \qquad \text{(C)}\ \frac{.9}{.7\times 5.3} \qquad \text{(D)}\ \frac{.9}{7\times .53} \qquad \text{(E)}\ \frac{.09}{.07\times .53}</math> | ||
[[1989 AJHSME Problems/Problem 13|Solution]] | [[1989 AJHSME Problems/Problem 13|Solution]] | ||
Line 60: | Line 104: | ||
== Problem 16 == | == Problem 16 == | ||
+ | |||
+ | In how many ways can <math>47</math> be written as the sum of two primes? | ||
+ | |||
+ | <math>\text{(A)}\ 0 \qquad \text{(B)}\ 1 \qquad \text{(C)}\ 2 \qquad \text{(D)}\ 3 \qquad \text{(E)}\ \text{more than 3}</math> | ||
[[1989 AJHSME Problems/Problem 16|Solution]] | [[1989 AJHSME Problems/Problem 16|Solution]] | ||
== Problem 17 == | == Problem 17 == | ||
+ | |||
+ | The number <math>\text{N}</math> is between <math>9</math> and <math>17</math>. The average of <math>6</math>, <math>10</math>, and <math>\text{N}</math> could be | ||
+ | |||
+ | <math>\text{(A)}\ 8 \qquad \text{(B)}\ 10 \qquad \text{(C)}\ 12 \qquad \text{(D)}\ 14 \qquad \text{(E)}\ 16</math> | ||
[[1989 AJHSME Problems/Problem 17|Solution]] | [[1989 AJHSME Problems/Problem 17|Solution]] | ||
== Problem 18 == | == Problem 18 == | ||
+ | |||
+ | Many calculators have a reciprocal key <math>\boxed{\frac{1}{x}}</math> that replaces the current number displayed with its reciprocal. For example, if the display is <math>\boxed{00004}</math> and the <math>\boxed{\frac{1}{x}}</math> key is depressed, then the display becomes <math>\boxed{000.25}</math>. If <math>\boxed{00032}</math> is currently displayed, what is the fewest number of times you must depress the <math>\boxed{\frac{1}{x}}</math> key so the display again reads <math>\boxed{00032}</math>? | ||
+ | |||
+ | <math>\text{(A)}\ 1 \qquad \text{(B)}\ 2 \qquad \text{(C)}\ 3 \qquad \text{(D)}\ 4 \qquad \text{(E)}\ 5</math> | ||
[[1989 AJHSME Problems/Problem 18|Solution]] | [[1989 AJHSME Problems/Problem 18|Solution]] | ||
Line 80: | Line 136: | ||
== Problem 21 == | == Problem 21 == | ||
+ | |||
+ | Jack had a bag of <math>128</math> apples. He sold <math>25\% </math> of them to Jill. Next he sold <math>25\% </math> of those remaining to June. Of those apples still in his bag, he gave the shiniest one to his teacher. How many apples did Jack have then? | ||
+ | |||
+ | <math>\text{(A)}\ 7 \qquad \text{(B)}\ 63 \qquad \text{(C)}\ 65 \qquad \text{(D)}\ 71 \qquad \text{(E)}\ 111</math> | ||
[[1989 AJHSME Problems/Problem 21|Solution]] | [[1989 AJHSME Problems/Problem 21|Solution]] |
Revision as of 10:41, 24 April 2009
Contents
- 1 Problem 1
- 2 Problem 2
- 3 Problem 3
- 4 Problem 4
- 5 Problem 5
- 6 Problem 6
- 7 Problem 7
- 8 Problem 8
- 9 Problem 9
- 10 Problem 10
- 11 Problem 11
- 12 Problem 12
- 13 Problem 13
- 14 Problem 14
- 15 Problem 15
- 16 Problem 16
- 17 Problem 17
- 18 Problem 18
- 19 Problem 19
- 20 Problem 20
- 21 Problem 21
- 22 Problem 22
- 23 Problem 23
- 24 Problem 24
- 25 Problem 25
- 26 See also
Problem 1
Problem 2
Problem 3
Which of the following numbers is the largest?
Problem 4
Estimate to determine which of the following numbers is closest to .
Problem 5
Problem 6
Problem 7
If the value of quarters and
dimes equals the value of
quarters and
dimes, then
Problem 8
Problem 9
There are boys for every
girls in Ms. Johnson's math class. If there are
students in her class, what percent of them are boys?
Problem 10
What is the number of degrees in the smaller angle between the hour hand and the minute hand on a clock that reads seven o'clock?
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
In how many ways can be written as the sum of two primes?
Problem 17
The number is between
and
. The average of
,
, and
could be
Problem 18
Many calculators have a reciprocal key that replaces the current number displayed with its reciprocal. For example, if the display is
and the
key is depressed, then the display becomes
. If
is currently displayed, what is the fewest number of times you must depress the
key so the display again reads
?
Problem 19
Problem 20
Problem 21
Jack had a bag of apples. He sold
of them to Jill. Next he sold
of those remaining to June. Of those apples still in his bag, he gave the shiniest one to his teacher. How many apples did Jack have then?