Difference between revisions of "1993 AJHSME Problems/Problem 1"

(See Also)
m
Line 4: Line 4:
  
 
==Solution==
 
==Solution==
A.The ordered pair <math>{-4,-9}</math> has a product of <math>-4*-9=36</math>
+
A. The ordered pair <math>{-4,-9}</math> has a product of <math>-4*-9=36</math>
  
 
B. The ordered pair <math>{-3,-12}</math> has a product of <math>-3*-12=36</math>
 
B. The ordered pair <math>{-3,-12}</math> has a product of <math>-3*-12=36</math>
Line 14: Line 14:
 
E. The ordered pair <math>{3/2, 24}</math> has a product of <math>3/2*24=36</math>
 
E. The ordered pair <math>{3/2, 24}</math> has a product of <math>3/2*24=36</math>
  
Since C is the only ordered pair which doesn't equal 36, <math>\boxed{C}</math> is the answer.
+
Since C is the only ordered pair which doesn't equal 36, <math>\boxed{\text{(C)}}</math> is the answer.
  
 
==See Also==
 
==See Also==
 
{{AJHSME box|year=1993|before=First<br />Question|num-a=2}}
 
{{AJHSME box|year=1993|before=First<br />Question|num-a=2}}

Revision as of 21:23, 22 December 2012

Problem

Which pair of numbers does NOT have a product equal to $36$? $\text{(A)}\ \{-4,-9\}\qquad\text{(B)}\ \{-3,-12\}\qquad\text{(C)}\ \left\{\frac{1}{2},-72\right\}\qquad\text{(D)}\ \{ 1,36\}\qquad\text{(E)}\ \left\{\frac{3}{2},24\right\}$

Solution

A. The ordered pair ${-4,-9}$ has a product of $-4*-9=36$

B. The ordered pair ${-3,-12}$ has a product of $-3*-12=36$

C. The ordered pair ${1/12, -72}$ has a product of $-36$

D. The ordered pair ${1, 36}$ has a product of $1*36=36$

E. The ordered pair ${3/2, 24}$ has a product of $3/2*24=36$

Since C is the only ordered pair which doesn't equal 36, $\boxed{\text{(C)}}$ is the answer.

See Also

1993 AJHSME (ProblemsAnswer KeyResources)
Preceded by
First
Question
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions