Difference between revisions of "1961 AHSME Problems/Problem 2"

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An automobile travels a/6 ''feet'' in ''r seconds''. If this rate is maintained for 3 minutes, how many ''yards'' does it travel in the 3 ''minutes''?
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== Problem ==
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An automobile travels <math>a/6</math> feet in <math>r</math> seconds. If this rate is maintained for <math>3</math> minutes, how many yards does it travel in <math>3</math> minutes?
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<math>\textbf{(A)}\ \frac{a}{1080r}\qquad
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\textbf{(B)}\ \frac{30r}{a}\qquad
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\textbf{(C)}\ \frac{30a}{r}\qquad
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\textbf{(D)}\ \frac{10r}{a}\qquad
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\textbf{(E)}\ \frac{10a}{r}    </math>
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==Solution==
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Use dimensional analysis.
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<cmath>\frac{a/6 \text{ feet}}{r \text{ seconds}} \cdot \frac{1 \text{ yard}}{3 \text{ feet}} \cdot \frac{60 \text{ seconds}}{1 \text{ minute}} \cdot 3 \text{ minutes}</cmath>
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<cmath>\frac{10a}{r} \text{ yards}</cmath>
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The answer is <math>\boxed{\textbf{(E)}}</math>.
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==See Also==
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{{AHSME 40p box|year=1961|num-b=1|num-a=3}}
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{{MAA Notice}}

Latest revision as of 18:30, 17 May 2018

Problem

An automobile travels $a/6$ feet in $r$ seconds. If this rate is maintained for $3$ minutes, how many yards does it travel in $3$ minutes?

$\textbf{(A)}\ \frac{a}{1080r}\qquad \textbf{(B)}\ \frac{30r}{a}\qquad \textbf{(C)}\ \frac{30a}{r}\qquad \textbf{(D)}\ \frac{10r}{a}\qquad \textbf{(E)}\ \frac{10a}{r}$

Solution

Use dimensional analysis. \[\frac{a/6 \text{ feet}}{r \text{ seconds}} \cdot \frac{1 \text{ yard}}{3 \text{ feet}} \cdot \frac{60 \text{ seconds}}{1 \text{ minute}} \cdot 3 \text{ minutes}\] \[\frac{10a}{r} \text{ yards}\] The answer is $\boxed{\textbf{(E)}}$.

See Also

1961 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
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All AHSME Problems and Solutions


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